Hi Peter!

2014-03-19 18:03 GMT-03:00 Peter Laursen <peter_laursen@webyog.com>:

Obivously this is the best solution

SELECT LENGTH("banana") - LENGTH( REPLACE("banana","n",""));
(so no need or a Stored Function)

.. however you may consider to replace LENGTH with CHAR_LENGTH, This is important if you use UTF8 and if you have non-ASCII characters (what you undoubtedly have as a Brazilian person (I guess you are?)). This example with the Spanish "ñ" character illustrates:

Yes =D Brazil heeh, sorry my english, i change some words and wrote sometimes as i think in portuguese (are you going? => you are going? kk portuguese have a different grammar)

No problem :) i'm using latin1 here at columns and server and client

SET NAMES utf8;
SELECT LENGTH("bañaña") - LENGTH( REPLACE("bañaña","ñ",""));
-- returns "4" (4 *bytes* more exactly) - and this result is not what your are after!

-- whereas
SET NAMES utf8;
SELECT CHAR_LENGTH("bañaña") - CHAR_LENGTH( REPLACE("bañaña","ñ",""));
-- returns "2" (2 *characters* more exactly) - and this is what you want.

yeap :) i know how to use charsets, char_length is the right function with multibyte text, but no problem :)

i considred a nice idea form adam

instead of remove the character, add a new character

length(replace('banana','n','n+'))-length('banana')

if i replace 'asdfasdf' with 'asdfasdf+', i have only one new character :) that's nice

-- Peter

thanks!

On Wed, Mar 19, 2014 at 6:16 PM, Federico Razzoli <federico_raz@yahoo.it> wrote:

When a PHP function does something you cannot do in SQL, you could call PHP from your queries using the Gearman UDF.

https://launchpad.net/gearman-mysql-udf

In most cases this should be faster than a stored function. I hope that in the future this will change, but who knows...

Regards,
Federico

--------------------------------------------
Mer 19/3/14, Roberto Spadim <roberto@spadim.com.br> ha scritto:

Oggetto: Re: [Maria-discuss] help - i'm not finding one sql function

A: "pslawek83" <pslawek83@o2.pl>
Cc: "Maria Discuss" <maria-discuss@lists.launchpad.net>
Data: Mercoledì 19 marzo 2014, 16:18

wow!
thanks kk i was trying to find a php like functionyour
idea is very nice :) thank you!
substr_count =>
(length(field)-length(replace('
','',field)))

/)

2014-03-19 12:16 GMT-03:00
pslawek83 <pslawek83@o2.pl>:

Hi
Roberto,
You'll have to replace char
=> empty and get the difference in length.

SELECT
(length("banana") - replace("n",
"", "banana"))

There's probably no
"standard" function to do that.

Dnia 19 marca
2014 15:51 Roberto Spadim <roberto@spadim.com.br>
napisał(a):

hi guys, i'm not finding a function to
return how many character i have, for example:

"banana"

i want a function that return 2 "n"
characters, example:
substr_count("banana","n") =>
2

sorry it a begginners question, but i didn't found
it in mysql/mariadb manual


--

Roberto Spadim
SPAEmpresarial
Eng. Automação e Controle

--
Roberto Spadim
SPAEmpresarialEng. Automação e
Controle

-----Segue allegato-----

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