Re: [Maria-discuss] AUTO_INCREMENT and partitioning

You can use no primary key, and just put a regular key (not unique key) on the auto_increment column. You must make sure that manual insertions don't create a duplicate if value.

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CREATE TABLE new ( id INT NOT NULL AUTO_INCREMENT, name VARCHAR(50), added DATE, KEY (id), ) PARTITION BY RANGE( TO_DAYS(added) ) ( PARTITION p0 VALUES LESS THAN (1990), PARTITION p1 VALUES LESS THAN (2000), PARTITION p2 VALUES LESS THAN MAXVALUE ) ;

Look at RANGE COLUMNS for a more natural way to partition by date:

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CREATE TABLE new ( id INT NOT NULL AUTO_INCREMENT, name VARCHAR(50), added DATE, PRIMARY KEY (id), ) PARTITION BY RANGE COLUMNS (added) ( PARTITION p0 VALUES LESS THAN ('1990-01-01'), .... PARTITION pmax VALUES LESS THAN MAXVALUE ) ; Sent from my iPhone

On Mar 12, 2016, at 5:16 AM, Guillaume Lefranc wrote:

The only solution is to make (id, added) a PK, because the partitioning column must always belong to unique key, if there is such. In your case I would change added type to DATETIME to avoid collision.

Regards

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On Sat, Mar 12, 2016 at 2:10 PM Ghazi Btissam wrote: Hi,

1- I have a table with a unique key which is calculated by the AUTO_INCREMENT feature, and I need to range partition it using a date field , is it possible and/or how to do it?

2- Is there a way to implement sequences for the primary key (like it exists in Oracle) or the AUTO_INCREMENT is the only one in MariaDb?

For example:

CREATE TABLE new ( id INT NOT NULL AUTO_INCREMENT, name VARCHAR(50), added DATE, PRIMARY KEY (id), ) PARTITION BY RANGE( TO_DAYS(added) ) ( PARTITION p0 VALUES LESS THAN (1990), PARTITION p1 VALUES LESS THAN (2000), PARTITION p2 VALUES LESS THAN MAXVALUE ) ; Thanks

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-- Guillaume Lefranc Remote DBA Services Manager MariaDB Corporation _______________________________________________ Mailing list: https://launchpad.net/~maria-discuss Post to : maria-discuss@lists.launchpad.net Unsubscribe : https://launchpad.net/~maria-discuss More help : https://help.launchpad.net/ListHelp